A gas sample with a volume of 5.3 L has a pressure of 745 mm Hg at 33°C. What is the pressure of the sample if the volume remains at 5.3 L but the temperature rises to 85°C?

Respuesta :

According to the Gay-Lussac which establishes that the pressure of a fixed volume of a gas is directly proportional to its temperature.

It is represented by the following formula:

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2},[/tex]

The pressure must be in atm units and temperature in kelvin. We calculate the conversion of each one:

[tex]745\text{ mmHg}\cdot\frac{1\text{ atm}}{760\text{ mmHg}}=0.98\text{ atm,}[/tex][tex]T_1=33C+273=306K,T_2=85C+273=358K\text{.}[/tex]

The final step is clear the final pressure which is P2 and replace the values there:

[tex]P_2=\frac{P_1\cdot T_2}{T_1}=\frac{0.98\text{ atm}\cdot358\text{ K}}{306\text{ K}}=1.146\text{ atm.}[/tex]

Then, we do the conversion from atm to mmHg:

[tex]1.146\text{ atm}\cdot\frac{760\text{ mmHg}}{1\text{ atm}}=870.96\text{ mmHg.}[/tex]

The final pressure is 870.96 mmHg.