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The last frame before the shuttle begins tomove is 140. The shuttle travels 56meters in 243 frames.(a) If each frame is 24 seconds what is thetime elapsed?(b) Assuming constant acceleration, at whatrate is the shuttle accelerating?(c) If the shuttle continued to move with thisacceleration, what speed would it reach 76s after launch?(d) If the shuttle traveled directly upwards, what would its altitude be at 76 s?

Respuesta :

A) if each frame is 24 seconds long and there 243 frames, the total time that elapses is 243 times 24, which equals 5832 seconds.

B) For this, we will need to use kinematics

inital velocity = 0 m/s

time = 5832 seconds

distance = 56 meters

acceleration = ?

We can use the formula

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