Problem
Find the polar coordinates for the point (-8,6)..
Solution
For this case we need to find the radius given by:
[tex]r=\sqrt[]{(-8)^2+(6)^2}=10[/tex]Now we can find the cosine of the angle on this way:
[tex]\cos \theta=-\frac{8}{10}=-0.8[/tex]And the sine would be:
[tex]\sin \theta=\frac{6}{10}=0.6[/tex]We can find the angle with this operation:
[tex]\theta=\cos ^{-1}(0.8)=36.87º[/tex]And then our answer would be:
[tex]r=10,\theta=36.87º[/tex]
