Respuesta :
SOLUTION:
Case: Volumes
[tex]\begin{gathered} Volume \\ V=l\times w\times h \end{gathered}[/tex]Where l is length, w is width and h is height.
Given:
Kyle has a storage box that is 2 ft. long, 3 ft. high, and has a volume of 12 ft. 3
Myla has a storage box that is 4 ft. high, 2 ft. long, and has a volume of 16 ft. 3
Method:
For Kyle,
Volume:
[tex]\begin{gathered} V=l\times w\times h \\ 12=2\times w\times3 \\ 12=6w \\ w=\frac{12}{6} \\ w=2ft \end{gathered}[/tex]For Myla,
Volume:
[tex]\begin{gathered} V=l\times w\times h \\ 16=2\times w\times4 \\ 16=8w \\ w=\frac{16}{8} \\ w=2ft \end{gathered}[/tex]The length and width of both boxes are 2ft and 2ft respectively. But they have different heights.
Final answer:
Both have a width of 2ft
Explanation: Same length and width, different heights hence different width
