Given data
*BE = 4x - 12
*DE = 2x + 8
At the point of intersection AC and BD, "x" is exactly split into halves.
Therefore
[tex]DE=EB[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} 2x+8=4x-12 \\ 2x-4x=-12-8 \\ -2x=-20 \\ x=\frac{-20}{-2} \\ x=10 \end{gathered}[/tex]Thus, the value of x equals to 10