SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Define the formula for probability
[tex]\text{Probability}=\frac{\text{number of required outcome }}{\text{number of total outcome}}[/tex]STEP 2: Get the required number of cards
[tex]\begin{gathered} A\text{ standard deck of playing cards has 52 cards therefore,} \\ \text{ number of total outcomes=52} \\ A\text{ standard deck of playing cards has }13\text{ spades} \\ A\text{ standard deck of playing cards has }4\text{ tens} \end{gathered}[/tex]STEP 3: Calculate the probability for getting a spade
[tex]\begin{gathered} \text{Pr(spades)}=\frac{\text{number of spades }}{\text{number of total outcome}} \\ \text{Pr(spades)}=\frac{13}{52}=\frac{1}{4} \end{gathered}[/tex]STEP 4: Calculate the probability for getting a ten
Since the cards were replaced, the number total outcomes remains the same
[tex]\begin{gathered} \text{Pr(ten)}=\frac{\text{number of ten}}{\text{number of total outcome}} \\ \text{Pr(ten)}=\frac{4}{52}=\frac{1}{13} \end{gathered}[/tex]STEP 5: Calculate the probability of selecting a spade and then selecting a ten
[tex]\begin{gathered} \text{The probability of selecting a spade and then a ten is;} \\ Pr(\text{spade)}\times Pr(ten) \\ =\frac{1}{4}\times\frac{1}{13}=\frac{1}{52} \end{gathered}[/tex]Hence, the probability of selecting a spade and then selecting a ten is 1/52
