WE ARE GIVEN:
• Concenntration NaOH (V1) = 0.12 M
,• Volume NaOH (V1) = ?mL
,• Concentation HCl(C2)= 0.24M
,• Volume HCl (V2) = 22.0 mL
We will calculate the volume of NaO required by applying the dilutions formula:
[tex]C_1V_1=C_2V_2[/tex]Substituting the given parameters into the above formula, we can calculate that Volume of NaOH required is :
[tex]\begin{gathered} V_1=\text{ }\frac{C_2V_2}{C_1} \\ \text{ =}\frac{0.24\text{ M* 22 mL}}{0.12\text{ M}} \\ \text{ }\therefore\text{ Volume NaOH= 44mL } \end{gathered}[/tex]