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The pressure, P (in Ibs/in2), that a 160-poundperson's shoe exerts on the ground whenwalking varies inversely with the area, A (inin2 ), of the sole of the shoe. When theshoes have a sole area of 40 in2, the pressureis 4 lbs/in2. Find an equation that relatesthese variables.[?]P =

The pressure P in Ibsin2 that a 160poundpersons shoe exerts on the ground whenwalking varies inversely with the area A inin2 of the sole of the shoe When thesho class=

Respuesta :

For this problem we know that for a 160-poundperson with an area of 40 in^2 the pressure is 4 lbs/in^2

So then we can conclude that the pressure is calculated with this operation:

[tex]P=\frac{160lb}{40in^2}=4\frac{lb}{in^2}[/tex]

Then we can create a generic formula forthe pressure and would be given by:

[tex]P=\frac{F}{A}[/tex]

Where F = force and A= area

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