Respuesta :

Given data

*The carbon-14 has a half-life is t = 5730 years

*The amount of quantity contained is n = 70 mg

*The given time is T = 17190 years

The expression for the radioactivity decay equation is given as

[tex]N=n(0.5)^{\frac{T}{t}}[/tex]

Substitute the values in the above expression as

[tex]\begin{gathered} N=70(0.5)^{\frac{17190}{5730}} \\ =8.75\text{ mg} \end{gathered}[/tex]