Solution:
Given the right triangle;
[tex]\begin{gathered} \sin\theta=\frac{opposite}{hypotenuse},\cos\theta=\frac{adjacent}{hypotenuse} \\ \end{gathered}[/tex]
Thus;
[tex]\sin x=\frac{6}{10},\cos y=\frac{6}{10}[/tex]
ANSWER: The ratios are both identical
