Input data
AE = 17
BE = 8
CD = 32
Procedure
[tex]\begin{gathered} \frac{AD}{AE}=\frac{CD}{BE} \\ \frac{AD}{17}=\frac{32}{8} \\ AD=17\cdot\frac{32}{8} \\ AD=68 \end{gathered}[/tex]
Now for DE
[tex]\begin{gathered} AE+DE=AD \\ DE=AD-AE \\ DE=68-17 \\ DE=51 \end{gathered}[/tex]The answer would be DE=51
