a1.Find the equation for a polynomial f(x) that satisfies the following:Degree 5Root of multiplicity 1 at x = 3• Root of multiplicity 2 at x = 2• Root of multiplicity 2 at x = -3y-intercept of (0, -216)f(x) =

we have that
the polynomial is of the form
f(x)=a(x-3)(x-2)^2(x+3)^2
where
a is the leading coefficient
y-intercept -----> (0,-216)
For x=0
substitute and solve for a
-216=a(0-3)(0-2)^2)(0+3)^2
-216=a(-3)(-2)^2(3)^2
-216=a(-3)(4)(9)
-216=-108a
a=2
therefore
[tex]f(x)=2(x-3)(x-2)^2(x+3)^2[/tex]