Answer:
• AB=13cm
,
• BC=33cm
,
• CD=13cm
,
• AD=33cm
Explanation:
The perimeter of the parallelogram = 92 cm
Let the length of side AB = x
AD is 7 more than twice AB.
[tex]AD=2x+7[/tex]
AB and AD are adjacent sides.
[tex]\begin{gathered} \text{Perimeter}=2(AB+AD) \\ 92=2(x+2x+7) \end{gathered}[/tex]
First, we solve for x:
[tex]\begin{gathered} 92=2(3x+7) \\ 3x+7=\frac{92}{2} \\ 3x+7=46 \\ 3x=46-7 \\ 3x=39 \\ x=\frac{39}{3} \\ x=13 \end{gathered}[/tex]
Therefore:
[tex]\begin{gathered} AB=13\operatorname{cm} \\ AD=2x+7 \\ =2(13)+7 \\ AD=33\operatorname{cm} \end{gathered}[/tex]
The side lengths of the parallelogram are:
• AB=13cm
,
• BC=33cm
,
• CD=13cm
,
• AD=33cm
