ANSWER
[tex]x-5[/tex]EXPLANATION
We want to divide the given expression:
[tex]\frac{x^2-3x-10}{x+2}[/tex]To do this, first, factor the numerator:
[tex]\begin{gathered} \frac{x^2-5x+2x-10}{x+2} \\ \\ \frac{x(x-5)+2(x-5)}{x+2} \\ \\ \frac{(x+2)(x-5)}{x+2} \end{gathered}[/tex]Now, divide the common bracketed terms in the fraction:
[tex]x-5[/tex]That is the answer.
