Let's factor the first equation:
[tex]x^2-11x+19=-5[/tex]first we need to write all the terms in the same side, then we have:
[tex]\begin{gathered} x^2-11x+19+5=0 \\ x^2-11x+24=0 \end{gathered}[/tex]now we factor the left side:
[tex](x-3)(x-8)=0[/tex]this implies that:
[tex]\begin{gathered} x-3=0 \\ x=3 \\ or \\ x-8=0 \\ x=8 \end{gathered}[/tex]Therefore the solutions for the equation are x=3 and x=8
