Given:
The mass of skater is m=60 kg.
The velocity of skater is v=4 m/s.
The kinetic energy of the skater is given as,
[tex]K=\frac{1}{2}mv^2[/tex]Plug in the known values,
[tex]\begin{gathered} K=\frac{1}{2}(60\text{ kg)(}4m/s)^2(\frac{1\text{ J}}{1kgm^2s^{-2}^{}}) \\ =120\text{ J} \end{gathered}[/tex]Thus, the kinetic energy of the skater is 120 J.
