Given:
The slope of the line, m=-2/3.
The coordinates of the point through which the line passes, (x1, y1)=(-3,-1).
The point-slope formula for the equation of a line can be written as,
[tex]y-y1=m(x-x1)[/tex]
Now, substitute the known values.
[tex]\begin{gathered} y-(-1)=\frac{-2}{3}(x-(-3) \\ y+1=\frac{-2}{3}(x+3) \end{gathered}[/tex][tex]\begin{gathered} y+1=\frac{-2}{3}x-\frac{2}{3}\times3 \\ y+1=\frac{-2}{3}x-2 \\ y=\frac{-2}{3}x-2-1 \\ y=\frac{-2}{3}x-3 \end{gathered}[/tex]
Therefore, the equation of the line is,
[tex]y=-\frac{2}{3}x-3[/tex]
