SOLUTION
We want to find the volume of the object below
The object is made up of a cone and a cylinder.
So volume of the object becomes
[tex]\text{volume of cone + volume of cylinder }[/tex]
Volume of the cone
[tex]\begin{gathered} \text{The cone and cylinder have a diameter of 6} \\ \text{radius }=\frac{diameter}{2}=\frac{6}{2}=3 \\ \text{volume of cone = }\frac{\pi r^2h}{3} \\ \text{height of the cone h = 5, } \\ \text{volume of cone = }\frac{3\times3^2\times5}{3} \\ =9\times5 \\ 45cm^3 \end{gathered}[/tex]
Voluem of the cylinder becomes
[tex]\begin{gathered} \text{volume = }\pi r^2h \\ \text{height of the cylinder h = 14 cm } \\ \text{volume = 3}\times3^2\times14 \\ =3\times9\times14 \\ =378cm^3 \end{gathered}[/tex]
Volume of the object becomes
[tex]undefined[/tex]
