Given:
Number of times rolled = 3
Number of outcomes = 8
Let's answer the following questions:
• (a). No even number on the first two rolls.
Where:
O represents Odd
E represents Even.
If no 2 even number is on the first two rolls, the outcome will be:
OOE; OOO
The probability will be:
[tex]P=\frac{number\text{ of outcomes}}{Total\text{ outcomes}}=\frac{2}{8}=\frac{1}{4}[/tex]
Therefore, the probability is 1/4.
• (b). Event B: Alternating even number and odd number.
This means even or odd numbers will not come consecutively.
We have the outcome:
EOE; OEO;
The probability is:
[tex]\begin{gathered} P=\frac{number\text{ of outcomes in Event B}}{total\text{ outcomes}}=\frac{2}{8} \\ \\ P=\frac{1}{4} \end{gathered}[/tex]
• Event C: ,An odd number on each of the first two rolls.
If an odd number is on each of the first two rolls, the outcomes will be:
OOE; OOO
The probability will be:
[tex]\begin{gathered} P=\frac{number\text{ of outcomes in Event C}}{total\text{ outcome}}=\frac{2}{8} \\ \\ P=\frac{1}{4} \end{gathered}[/tex]
ANSWER:
Event A: OOE and OOO
Probability = 1/4
Event B: EOE and OEO;
Probability = 1/4
Event C: OOE and OOO
Probability = 1/4
