Simplify the given expression as shown below
[tex]\begin{gathered} e^a=47.38 \\ \Rightarrow ln(e^a)=ln(47.38) \\ \Rightarrow aln(e)=ln(47.38) \\ and \\ ln(e)=1 \\ \Rightarrow a=ln(47.38) \end{gathered}[/tex]
Therefore, the answer is ln(47.38)=a, option A.
