The Solution:
Given:
[tex]\begin{gathered} f(x)=x^2+2 \\ \\ g(x)=-x+4 \end{gathered}[/tex]
We are required to find:
[tex]\frac{g\mleft(b\mright)}{f(b)}[/tex]
So,
[tex]\begin{gathered} f(b)=b^2+2 \\ \\ g(b)=-b+4 \end{gathered}[/tex][tex]\frac{g(b)}{f(b)}=\frac{-b+4}{b^2+2}[/tex]
Therefore, the correct answer is:
[tex]\frac{-b+4}{b^{2}+2}[/tex]
