,In this case we will use Newton's second law
[tex]F=ma[/tex]Where F is the force, m is the mass and a is the acceleration
In our case
F=-644 N
m=1,371 kg
a=?
[tex]644=1371(a)[/tex]We isolate the a
[tex]a=\frac{-644}{1371}=-0.47m/s^2[/tex]ANSWER
-0.47 m/s^2
