hello
the total numbers of coin in the pockets are
[tex]5+8=13[/tex]the probablility of the first coin to be a nickel is
[tex]\frac{5}{13}[/tex]the probability of the second coin is a dime is
[tex]\frac{8}{12}=\frac{2}{3}[/tex]the probability that the first coin is a nickel and the second coin a dime is
[tex]\frac{5}{13}\times\frac{2}{3}=\frac{10}{39}[/tex]from the calculations above, the probability that the first coin is a nickel and the second coin is a dime is 10/39
