Respuesta :
Given:
[tex]x+3y=15[/tex][tex]4x+y=6[/tex]To find whether (3, -6) is a solution to both equations, we can substitute the given values to both of the equation.
Equation 1: x + 3y = 15
Substitute (3, -6)
[tex]x+3y=15[/tex][tex](3)+3(-6)=15[/tex][tex]3-18=15[/tex][tex]-15\ne15[/tex]From here, we can already see that (3, -6) is not a solution to x + 3y = 15.
To check, let us also try substituting these values to the second equation.
Equation 2: 4x + y = 6
Substitute (3, -6)
[tex]4x+y=6[/tex][tex]4(3)+(-6)=6[/tex][tex]12-6=6[/tex][tex]6=6[/tex]The second equation has (3, -6) as its solution. However, since it is a system of equations, both equation should have the same solutions.
Therefore, (3, -6) is not a solution to the given system. The answer would be false.
