Given:
Given a diamgram of line DC and triangle ABC.
[tex]\begin{gathered} \angle EAC=(76-x)\degree \\ \\ \angle BAE=34\degree \\ \\ \angle BAD=(4x-8)\degree \end{gathered}[/tex]
Required:
To find the value of x.
Explanation:
From the figure DC is straight line.
The angle of straight line is 180 degree.
So
[tex]\begin{gathered} 76-x+34+4x-8=180 \\ 3x+102=180 \\ 3x=180-102 \\ 3x=78 \\ x=\frac{78}{3} \\ x=26 \\ \end{gathered}[/tex]
Final Answer:
[tex]x=26\degree[/tex]
