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(L012) Grades on Exam 1 for College Algebra are normally distributed with a mean
of 73 and a standard deviation of 6. What is the z-score for a grade of 62?
0 -1.83
-0.77
O
0.77
1.83

Respuesta :

For a normal distribution, we can determine the z-socre by means of the following formula:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Where μ is the mean and σ is the standard deviation. By replacing 62 for x, 73 for μ and 6 for σ, we get:

[tex]z=\frac{62-73}{6}=-1.83[/tex]

Then, the z-score value is -1.83

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