Given:
In a right triangle, ACB
AC=12
CB=9
AB=15
To choose two angles with a cosine ratio of 3/5:
[tex]\begin{gathered} \cos B=\frac{BC}{AB} \\ \cos B=\frac{9}{15} \\ \cos B=\frac{3}{5} \end{gathered}[/tex]
Similarly, for a right triangle MPN,
The corresponding angle to angle B is N.
So, the answer is,
Angle B and Angle N.
