Given,
The expression is,
[tex]f(x)=-x^2+2x+5[/tex]
Required
The value of f(x) at x = -1, 0, 1, 2, 3.
The value of f(x) when x = -1.
[tex]f(-1)=-(-1)^2+2(-1)+5=2[/tex]
The value of f(x) when x = 0.
[tex]f(0)=-(0)^2+2(0)+5=5[/tex]
The value of f(x) when x = 1.
[tex]f(1)=-(1)^2+2(1)+5=6[/tex]
The value of f(x) when x = 2.
[tex]f(1)=-(2)^2+2(2)+5=5[/tex]
The value of f(x) when x = 3.
[tex]f(1)=-(3)^2+2(3)+5=2[/tex]
Hence, the value of f(x) at x = -1 , 0,1, 2, 3 is obtained.
