In this problem, we want to answer an application problem including velocity.
We are given
[tex]v=\sqrt{19.6h}[/tex]
where v represents the velocity and h represents the height in meters.
If we are dropping an object from a height of 22.3 meters, we want to know the velocity when it hits the ground.
We can subsitute the value of h into the formula to get:
[tex]v=\sqrt{19.6(22.3)}\approx20.9[/tex]
So, the velocity will be 20.9 meters per second.
