we have the expression
[tex]\sqrt[\square]{169a^2b^2}[/tex]Remember that
169=13^2
substitute
[tex]\sqrt[\square]{169a^2b^2}=\sqrt[\square]{13^2a^2b^2}[/tex]simplify
[tex]\sqrt[\square]{13^2a^2b^2}=13ab[/tex]Part 2
If the expression is
[tex]\sqrt[\square]{16\cdot9\cdot a^2\cdot b^2}[/tex]16=4^2
9=3^2
substitute and simplify
the answer will be
(4)(3)(a)(b)=12ab
