Given the inequality;
[tex]3y-2x\leq12[/tex]
Let's convert it to slope intercept form;
[tex]\begin{gathered} 3y-2x\leq12 \\ Add\text{ 2x from both sides and divide both sides by 3;} \\ 3y-2x+2x\leq12+2x \\ 3y\leq2x+12 \\ \frac{3y}{3}\leq\frac{2x}{3}+\frac{12}{3} \\ y\leq\frac{2}{3}x+4 \end{gathered}[/tex]
So, the slope of the line is 2/3 which is positive, and the intercept on the y axis is 4.
