the slope-intercept should be in this form
[tex]y=mx+b[/tex]where m should be the value that changes with time and b the fixed charges
[tex]y=1.5x+4[/tex]replace in the equation like this
[tex]\begin{gathered} \text{when x=2} \\ y=1.5\cdot(2)+4 \\ y=3+4 \\ y=7 \end{gathered}[/tex][tex]\begin{gathered} \text{when x=}4 \\ y=1.5\cdot(4)+4 \\ y=6+4 \\ y=10 \end{gathered}[/tex][tex]\begin{gathered} \text{when x=}6 \\ y=1.5\cdot(6)+4 \\ y=9+4 \\ y=13 \end{gathered}[/tex][tex]\begin{gathered} \text{when x=}8 \\ y=1.5\cdot(8)+4 \\ y=12+4 \\ y=16 \end{gathered}[/tex]replace values in the table