We know that
• The slope is -2.
,
• The point is (-3,8)
First, we have to find the equation of the line. We use the point-slope formula.
[tex]y-y_1=m(x-x_1)[/tex]
Let's replace the slope and the point.
[tex]\begin{gathered} y-8=-2(x-(-3)) \\ y-8=-2x-6 \\ y=-2x-6+8 \\ y=-2x+2 \end{gathered}[/tex]
Once we have the equation, we find the solution when y = 0.
[tex]\begin{gathered} 0=-2x+2 \\ -2=-2x \\ x=-\frac{2}{-2} \\ x=1 \end{gathered}[/tex]
Therefore, the zero is 1.
