SamrahM230427 SamrahM230427

29-10-2022
Mathematics

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solve by factorization 48n^2 -3n^4=0

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CamaniT103450 CamaniT103450

29-10-2022

Given:-

[tex]48n^2-3n^4=0[/tex]

To find the value by factorization.

So now we simplify,

[tex]\begin{gathered} 48n^2-3n^4=0 \\ 3n^2(16-n^2)=0 \\ 3n^2=0,16-n^2=0 \\ n=0,n^2=16 \\ n=0,n=14 \end{gathered}[/tex]

So the values are 0 and 14.

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