Solution
We have the following two equations given:
2x + 3y = -3
We can solve for x and we got:
[tex]x=\frac{-3-3y}{2}[/tex]We can replace into the second equation and we got:
[tex]3(\frac{-3-3y}{2})+5y=-9[/tex]And solving for y we got:
[tex]-\frac{9}{2}-\frac{9}{2}y+5y=-9[/tex]then the value of y would be:
[tex]y=2\cdot(-\frac{9}{2})=-9[/tex]And solving for x we got:
[tex]x=\frac{-3-3(-9)}{2}=12[/tex]