Given the standar form of the circle
[tex](x-h)^2+(y-k^2)=r^2[/tex]
and given the expression
[tex]y^2+2x+x^2=24y−120[/tex][tex]y^2+2x+x^2-24y+120=0[/tex][tex](x^2+2x)+(y^2-24y)+120=0[/tex][tex](x^2+2x+1)+(y^2-24y+144)-25=0[/tex][tex](x+1)^2+(y-12)^2=25[/tex][tex](x-(-1))^2+(y-12)^2=5^2[/tex]
the circumference have r=5
and center in (-1 , 12)
