We have the following inequality:
[tex]13(x-6)>2[/tex]and we need to solve for x.
Then, by dividing both sides by 13, we have
[tex]x-6>\frac{2}{13}[/tex]and by adding 6 to both sides, we obtain
[tex]x>\frac{2}{13}+6[/tex]which can be written as
[tex]x>\frac{2}{13}+\frac{78}{13}[/tex]so, we can add the fractions and get
[tex]x>\frac{80}{13}[/tex]Finally, by converting this result into mixed fraction form, we have
[tex]x>6\frac{2}{13}[/tex]Therefore, the answer is: x is greater than 6.
