The area of 0.195 to the right of z under the normal curve is
[tex]P(ZSketch the normal curve and shade the area of 0.195 to the right of "z" under the normal curve.Since the total area under the normal curve is 1. therefore, the area to the left of normal is 1-0.195 = 0.805.
[tex]P(ZRefer Standard normal table/Z-table, Lookup for z-score corresponding to area 0.805 to the left of the normal curve[tex]P(Z<0.86)=0.805[/tex]Hence the value of z is 0.86.
