SOLUTION:
Step 1:
In this question, we are given the following:
A baseball manager is determining the batting order for the team.
The team has 9 players, but the manager definitely wants the pitcher to bat last. How many batting orders are possible.
Step 2:
The details of the solution are as follows:
Since the pitcher bats last, there is only one choice for the 9th slot.
For the 1st slot, there are 8 choices remaining.
For the 2nd slot, there are 7 choices remaining, etc.
So the number of possible batting orders is:
[tex]8\text{ x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 8}!=\text{ 40320 orders}[/tex]
