Therefore,
[tex]\begin{gathered} 2y+5x=10 \\ 2y=-5x+10 \\ y=-\frac{5}{2}x+5 \end{gathered}[/tex]A.
[tex]y-\text{intercept}=5[/tex][tex]\begin{gathered} 0=-\frac{5}{2}x+5 \\ -5=-\frac{5}{2}x \\ -10=-5x \\ x=\frac{10}{5} \\ x=2 \\ \\ x-\text{intercept}=2 \end{gathered}[/tex]B.