Point P = (-4, -3)
Slope = 5/3
First we will calculate the equation of the line
[tex]\begin{gathered} b=y-mx \\ b=-3-(5/3)\cdot(-4) \\ b=-3+20/3 \\ b=11/3 \end{gathered}[/tex]The full equation would be
[tex]y=\frac{5}{3}x+\frac{11}{3}[/tex]Second point
x = -3
[tex]\begin{gathered} y=\frac{5}{3}(-3)+\frac{11}{3} \\ y=-5+\frac{11}{3} \\ y=-\frac{4}{3} \end{gathered}[/tex]The ordered pair would be (-3, -4/3)
