Answer
Pressure 2 = 13.49 atm
Explanation
Given:
Temperature 1 = -131 °C = 142 K
Temperature 2 = 110 °C = 383 K
Pressure 1 = 5.0 atm
Solution
To solve this problem we will use Gay-Lussac's Law
P1/T1 = P2/T2
P2 = P1T2/T1
P2 = (5.0 atm x 383 K)/142 K
P2 = 13.49 atm
