Given data
*The given positive charge is q = 2.0 C
*The second positive charge is Q = 3.0 C
*The distance between the charges is r = 80 m
The formula for the magnitude of the force between the two charges is given as
[tex]F=\frac{\text{kqQ}}{r^2}[/tex]
*Here k is the Coulomb's constant
Substitute the values in the above expression as
[tex]\begin{gathered} F=\frac{(9\times10^9)(2.0)(3.0)}{(80)^2} \\ =8.4\times10^6\text{ N} \end{gathered}[/tex]
Hence, the correct option is (a)
