Inscribed arc on a circle
We have that the arc NQ is:
The arc is a line and the area is a region of the circle.
We have that 90º is 1/4 of 360º:
360º/4 = 90º
Since the angle m∠NPQ is 90º, then the arc NQ is 1/4 of the whole circumference ( which is a 360º arc):
Answer: D. 1/4 of the circumference of circle P
