Given:
Two dice are rolled.
Required:
What is the probability that the sum of the numbers rolled is either 6 or 8?
Explanation:
The probability,
[tex]Probability(P)=\frac{\text{ Numebr of favorable outcomes}}{\text{ Total number of outcomes}}[/tex]There are 36 possible results when two dice are rolled.
The results add to 6 are 1 + 5, 2 + 4, 3 + 3, 4 + 2, 5 + 1.
The results add to 8 are 2 + 6, 3 + 5, 4 + 4, 5 + 3, 6 + 2.
5 rolls of two dice add to 6 and 5 rolls add to 8.
So,
[tex]\begin{gathered} P=\frac{10}{36} \\ P=\frac{5}{18} \end{gathered}[/tex]Answer:
[tex]\text{ The required probability equals }\frac{5}{18}.[/tex]