parallel line has identical slope . Therefore parallel line passing through (0, 1) have the same slope.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ 3x+\frac{3}{4}y=2 \\ \frac{3}{4}y=2-3x \\ mul\text{ltiply through by }\frac{4}{3} \\ y=2(\frac{4}{3})-3x(\frac{4}{3}) \\ y=\frac{8}{3}-4x \\ y-y_1=m(x-x_1) \\ m=-4 \\ y-1=-4(x-0) \\ y-1=-4x \\ y=-4x+1 \end{gathered}[/tex]
The equation is
y = -4x + 1
