From the given question
There are given that the log
[tex]\log _29[/tex]
Now,
From the change of base formula:
[tex]\log _a(x)=\frac{\log_bx}{\log_ba}[/tex]
Then,
[tex]\begin{gathered} \log _2(9)=\frac{\log _{10}9}{\log _{10}2} \\ =\frac{0.95}{0.30} \\ =3.166 \end{gathered}[/tex]
Hence, the value of given log function is 3.166.
