Answer:
(-inf, 0.75]
Explanation:
In order to solve the inequality
[tex]3x+2\ge7x-1[/tex]
we first subtract 2 from both sides to get:
[tex]3x\ge7x-1-2[/tex]
next, subtracting 7x from both sides gives
[tex]3x-7x\ge-1-2[/tex][tex]-4x\ge-3[/tex]
Now we divide both sides by - 4. Remember that whenever we divide by a negative number, the equality changes sign. Therefore, the above becomes
[tex]-\frac{4x}{-4}\le-\frac{3}{-4}[/tex][tex]x\le\frac{3}{4}[/tex]
since in decimal form 3/4 = 0.75, the above becomes
[tex]\boxed{x\le0.75}[/tex]
Hence, all values of x less than or equal to 0.75 satisfy the inequality.
Now how do we write x ≤ in the interval notation?
The answer is
[tex](-\infty,0.75\rbrack[/tex]
which means all values of from ( and not including) -infinity to 0.75 (included) satisfy the inequality.