The weight of the solution is 13 1/3 ounces.
Each container can contain 5/12 ounces.
The number of container required can be determined as,
[tex]\begin{gathered} N=\frac{13\frac{1}{3}}{\frac{5}{12}} \\ =\frac{\frac{40}{3}}{\frac{5}{12}} \\ =\frac{40}{3}\times\frac{12}{5} \\ =32 \end{gathered}[/tex]Thus, the requried number of containers is 32.
