The given equation;
[tex]\frac{3x-5}{2}=-7[/tex]
Apply cross multiplication;
[tex]\begin{gathered} \frac{3x-5}{2}=-7 \\ 3x-5=-7\times2 \\ 3x-5=-14 \end{gathered}[/tex]
Now, add 5 on both side as;
[tex]\begin{gathered} 3x-5+5=-14+5 \\ 3x=-9 \end{gathered}[/tex]
Divide both side by 3;
[tex]\begin{gathered} \frac{3x}{x}=-\frac{9}{3} \\ x=-3 \end{gathered}[/tex]
Hence proof
